a) (x-1).(x-3)=0
\(\Rightarrow\left\{\begin{matrix}x-1=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=1\\x=3\end{matrix}\right.\)
Vậy x = 1; x = 3
b) (3-x).(x-3)=0
\(\Rightarrow\left\{\begin{matrix}3-x=0\\x-3=0\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=3\\x=3\end{matrix}\right.\)
Vậy x = 3
c) x.(x+1)=0
\(\Rightarrow\left\{\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left\{\begin{matrix}x=0\\x=-1\end{matrix}\right.\)
Vậy x = 0; x = -1
\(\left(x-1\right).\left(x-3\right)=0\)
\(\Rightarrow\left[\begin{matrix}x-1=0\\x-3=0\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=1\\x=3\end{matrix}\right.\)
\(\left(3-x\right).\left(x-3\right)=0\)
\(\Rightarrow\left[\begin{matrix}3-x=0\\x-3=0\end{matrix}\right.\Rightarrow x=3\)
\(x.\left(x+1\right)=0\)
\(\Rightarrow\left[\begin{matrix}x=0\\x-1=0\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=0\\x=1\end{matrix}\right.\)
Có \(\left(x-1\right).\left(x-3\right)\)
\(\Rightarrow\begin{matrix}x-1=0\\x-3=0\end{matrix}\)\(\Rightarrow\begin{matrix}x=1\\x=3\end{matrix}\)
Vậy x=1 hoặc x=3
(x-1).(x-3)=0
x - 1 = 0 hoặc x - 3 = 0
x = 0 +1 hoặc x = 0 + 3
x = 1 hoặc x = 3
Vậy x = 1 hoặc x = 3
(3-x).(x-3)=0
3 - x = 0 hoặc x - 3 = 0
x = 0 +3 hoặc x = 0 + 3
x = 3 hoặc x = 3
x.(x+1)=0
x = 0 hoặc x + 1 = 0
x = 0 hoặc x = 0 - 1
x = 0 hoặc x = -1
Vậy x = 0 hoặc x = -1