\(\left(x+1\right)\left(4x-3\right)=\left(2x+5\right)\left(1+x\right)\)
\(\Leftrightarrow4x^2+x-3=2x^2+7x+5\)
\(\Leftrightarrow2x^2-6x-8=0\)
\(\Leftrightarrow2x\left(x+1\right)-8\left(x+1\right)=0\)
\(\Leftrightarrow2\left(x+1\right)\left(x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-1\\x=4\end{matrix}\right.\)
Vậy tập nghiệm của pt là:\(S=\left\{-1;4\right\}\)
\(\left(x+1\right)\left(4x-3\right)=\left(2x+5\right)\left(1+x\right)\)
\(\Rightarrow4x-3=2x+5\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)
Vậy x = 4
