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Question

viết kết quả sau dưới dạng một lũy thừa

a, 1253 :254  ;      166:42      ;  278:94      ; 1255:253      ;   414:528

b, 12n :22n    ;       644.165.420

Tài Nguyễn Tuấn · Accepted Answer

a) $125^3:25^4=(5^3)^3:(5^2)^4=5^9:5^8=5^1$

$16^4:4^2=(4^2)^4:4^2=4^8:4^2=4^6$

$27^8:9^4=(3^3)^8:(3^2)^4=3^{24}:3^8=3^{16}$

$125^5:25^3=(5^3)^5:(5^2)^3=5^{15}:5^6=5^9$

$4^{14}:5^{28}=(2^2)^{14}:5^{28}=2^{28}:5^{28}=(\dfrac{2}{5})^{28}$

b) $12^n:2^{2n}=12^n:(2^2)^n=12^n:4^n=3^n$

$64^4.16^5.4^{20}=(4^3)^4.(4^2)^5.4^{20}=4^{12}.4^{10}.4^{20}=4^{42}$Câu trả lời: a) $125^3:25^4=(5^3)^3:(5^2)^4=5^9:5^8=5^1$

$16^4:4^2=(4^2)^4:4^2=4^8:4^2=4^6$

$27^8:9^4=(3^3)^8:(3^2)^4=3^{24}:3^8=3^{16}$

$125^5:25^3=(5^3)^5:(5^2)^3=5^{15}:5^6=5^9$

$4^{14}:5^{28}=(2^2)^{14}:5^{28}=2^{28}:5^{28}=(\dfrac{2}{5})^{28}$

b) $12^n:2^{2n}=12^n:(2^2)^n=12^n:4^n=3^n$

$64^4.16^5.4^{20}=(4^3)^4.(4^2)^5.4^{20}=4^{12}.4^{10}.4^{20}=4^{42}$

Đại số lớp 6