Gọi hợp chất có dạng \(C_xCu_yO_z\)
Ta có: \(100\%=20\%+40\%+O\)
\(\Rightarrow O=40\%\)
Ta có:
\(\dfrac{M_{C_x}}{\%C}=\dfrac{M_{Cu_y}}{\%Cu}=\dfrac{M_{O_z}}{\%O}=\dfrac{M_{C_xCu_yO_z}}{100}\)
\(\Leftrightarrow\dfrac{12x}{20}=\dfrac{64y}{40}=\dfrac{16z}{40}=\dfrac{64}{100}\)
\(\Leftrightarrow\dfrac{12x}{20}=\dfrac{64}{100}\)
\(\Rightarrow x=1\)
\(\Leftrightarrow\dfrac{64y}{40}=\dfrac{64}{100}\)
\(\Rightarrow y\approx1\)
\(\Leftrightarrow\dfrac{16z}{40}=\dfrac{64}{100}\)
\(\Rightarrow z=1,6\approx2\)
Vậy ta có CTHH là \(CCuO_2\) .
Chắc sai :v