(x-1)^2+(y-3)^2=9
=>R=3; I(1;3)
Tọa độ tâm I1 là:
\(\left\{{}\begin{matrix}x=1\cdot cos90-3\cdot sin90=-3\\y=1\cdot sin90+3\cdot cos90=1\end{matrix}\right.\)
Tọa độ I2 là:
\(\left\{{}\begin{matrix}x'=-x=3\\y'=y=1\end{matrix}\right.\)
=>(C'): (x-3)^2+(y-1)^2=9