\(AB=\sqrt{\left(-3-2\right)^2+\left(2-4\right)^2}=\sqrt{29}\)
\(AC=\sqrt{\left(4-2\right)^2+\left(-1-4\right)^2}=\sqrt{29}\)
\(BC=\sqrt{\left(4+3\right)^2+\left(-1-2\right)^2}=\sqrt{58}\)
Vì AB^2+AC^2=BC^2
nên ΔBAC vuông tại A
\(S_{ABC}=\dfrac{1}{2}\cdot AB\cdot AC=\dfrac{29}{2}\)