a) Vì \(\widehat{xOz}>\widehat{xOy}\) \(\left(130^o>50^o\right)\)
\(\Rightarrow\) Tia Oy nằm giữa 2 tia Ox và Oz
b) Theo câu a, ta có :
\(\widehat{xOy}+\widehat{yOz}=\widehat{xOz}\)
\(\Rightarrow50^o+\widehat{yOz}=130^o\)
\(\Rightarrow\widehat{yOz}=130^o-50^o\)
\(\Rightarrow\widehat{yOz}=80^o\)
c) Vì Ot là tia phân giác của góc \(\widehat{xOz}\)
\(\Rightarrow\)\(\widehat{xOt}=\widehat{zOt}=\frac{\widehat{xOz}}{2}=\frac{130^o}{2}=65^o\)
Ta có : \(\widehat{xOt}>\widehat{xOy}\) \(\left(65^o>50^o\right)\)
\(\Rightarrow\widehat{xOy}+\widehat{yOt}=\widehat{xOt}\)
\(\Rightarrow50^o+\widehat{yOt}=65^o\)
\(\Rightarrow\widehat{yOt}=65^o-50^o\)
\(\Rightarrow\widehat{yOt}=15^o\)
Vậy....
