Question

Tính:

a) \(\dfrac{2}{5}+\dfrac{6}{5}\)                           b) \(\dfrac{4}{9}+\dfrac{7}{9}\)                       c) \(\dfrac{6}{7}-\dfrac{4}{7}\)                  d) \(\dfrac{17}{19}-\dfrac{12}{19}\)

Answer 1

a: \(\dfrac{2}{5}+\dfrac{6}{5}=\dfrac{2+6}{5}=\dfrac{8}{5}\)

b: \(\dfrac{4}{9}+\dfrac{7}{9}=\dfrac{4+7}{9}=\dfrac{11}{9}\)

c: \(\dfrac{6}{7}-\dfrac{4}{7}=\dfrac{6-4}{7}=\dfrac{2}{7}\)

d: \(\dfrac{17}{19}-\dfrac{12}{19}=\dfrac{17-12}{19}=\dfrac{5}{19}\)