\(\left(x^3-3x^2+x-2\right)\left(4-x\right)\)
\(=4.\left(x^3-3x^2+x-2\right)-x.\left(x^3-3x^2+x-2\right)\)
\(=4.x^3-4.3x^2+4.x-4.2-x.x^3+x.3x^2-x.x+x.2\)
\(=4x^3-12x^2+4x-8-x^4+3x^3-x^2+2x\)
\(=\left(4x^3+3x^3\right)-\left(12x^2-x^2\right)+\left(4x+2x\right)-8-x^4\)
\(=7x^3-11x^2+6x-8-x^4\)
(x3 - 3x2 +x-2)(4-x)=4(x3 -3x2 +x - 2)-x(x3 -3x2 +x-2)
=4x3 -12x2 +4x-8-x4 +3x3 -x2 +2x
=7x3-12x2 +6x-8-x4
1 k làm quen nha