Gọi O là tâm đáy \(\Rightarrow SO\perp\left(ABCD\right)\)
\(\Rightarrow\widehat{SAO}=60^0\)
\(AO=\dfrac{AC}{2}=\dfrac{1}{2}.a\sqrt{2}\)
\(\Rightarrow SO=AO.tan\widehat{SAO}=\dfrac{a\sqrt{6}}{2}\)
\(\Rightarrow V=\dfrac{1}{3}SO.S_{ABCD}=\dfrac{a^3\sqrt{6}}{6}\)