Ta có:
45 . 16 - 17 = 45. (15 +1) - 17
= 45 . 15 + 1.45 - 17
= 45 . 15 + (45 - 17)
= 45 . 15 + 28
vậy \(\dfrac{45.16-17}{45.15+28}=\dfrac{45.15+28}{45.15+28}=1\)
\(\dfrac{45.16-17}{28+45.15}\)
= \(\dfrac{45.\left(15+1\right)-17}{28+45.15}\)
= \(\dfrac{45.15+\left(45-17\right)}{28+45.15}\)
= \(\dfrac{45.15+27}{27+45.15}\)
= 1
~ Chúc bạn học giỏi ! ~