. mC4H10=80%\100%.10=8kg
mCH4=18%\100%.10=1,8kg
2C4H10 + 13O2 t0→→t0 8CO2 + 10H2O
Cứ 116 g → 416 g
Hay 116 kg → 416 kg
Vậy 8 kg → x kg
=> x = (8.416) :116=28,69 kg
CH4 + 2O2 t0→→t0 CO2 + 2H2O
Cứ 16 g → 64 g
Hay 16 kg → 64 kg
Vậy 1,8 kg → y kg
=> y= (1,8.64) :16=7,2kg