Question

Tính hợp lý các biểu thức sau

A=\(49\dfrac{8}{23}-\left(5\dfrac{7}{32}+14\dfrac{8}{23}\right)\)

B=\(6\dfrac{3}{8}+5\dfrac{1}{2}\)

C=\(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

Làm giúp mình với à, mình tick cho

Answer 1

(mk ko ghi lại đề đâu nhé)

A= \(49\dfrac{8}{23}-5\dfrac{7}{32}-14\dfrac{8}{23}\)

= \(49\dfrac{8}{23}-14\dfrac{8}{23}-5\dfrac{7}{32}\)

= 35 - \(\dfrac{7}{32}\)

= 34 +\(\dfrac{32}{32}-\dfrac{7}{32}\)

= 34 + \(\dfrac{25}{32}\) = 34\(\dfrac{25}{32}\)

Answer 2

B = (6+5) + (\(\dfrac{3}{8}+\dfrac{1}{2}\))

= 11 + \(\dfrac{7}{8}\)

= 11\(\dfrac{7}{8}\)

Answer 3

C = \(8\dfrac{2}{7}-3\dfrac{4}{9}-4\dfrac{2}{7}\)

= \(8\dfrac{2}{7}-4\dfrac{2}{7}-3\dfrac{4}{9}\)

= 4 - 3\(\dfrac{4}{9}\)

= \(3+\dfrac{9}{9}-3-\dfrac{4}{9}\)

= \(\dfrac{5}{9}\)