Question

Tính hợp lí

0,5+1/3+0,4+5/7+1/6-4/35+1/41

Answer 1

\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)

\(=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)

\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{4}{35}\right)+\dfrac{1}{41}\)

\(=\left(\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}\right)+\left(\dfrac{14}{35}+\dfrac{25}{35}-\dfrac{4}{35}\right)+\dfrac{1}{41}\)

\(=\dfrac{3+2+1}{6}+\dfrac{14+25-4}{35}+\dfrac{1}{41}\)

\(=1+1+\dfrac{1}{41}\)

\(=2+\dfrac{1}{41}\)

\(=2\dfrac{1}{41}=\dfrac{83}{41}\)