\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=2^8\)
8^10+4^10/8^4+4^11
=(2^3)^10+(2^2)10/(2^3)^4+(2^2)^11
=2^30+2^20/2^12+2^22
=2^20(2^10+1)/2^12(1+2^10)
=2^8=256
vậy giá trị biểu thức =256