Thế thì tick cho luôn đi, tui trả lời đây nè! :)))
a) \(3-\left(\dfrac{6}{7}\right)^0+\left(\dfrac{1}{2}\right)^2:2\)
\(=3+\left(\dfrac{6}{7}\right)^0+\dfrac{1}{4}.\dfrac{1}{2}\)
\(=3+1+\dfrac{1}{8}=4+\dfrac{1}{8}\)
\(=\dfrac{33}{8}\)
b) \(64.2^3.\dfrac{1}{32^2}\)
\(=2^6.2^4.\dfrac{1}{32^2}=2^{10}.\dfrac{1}{32^2}\)
\(=\left(2^5\right)^2.\dfrac{1}{32^2}=32^2.\dfrac{1}{32^2}\)
= 1
c) \(\left(-2\right)^3+2^2+\left(-1\right)^{20}+\left(-2\right)^0\)
\(=-8+4+1+1\)
\(=-8+6=-2\)
d) \(2^3+3.\left(\dfrac{1}{2}\right)^0-\left(\dfrac{1}{2}\right)^2.4\left[\left(-2\right)^2:\dfrac{1}{2}\right].8\)
\(=8+3.1-\dfrac{1}{4}.4+\left[4:\dfrac{1}{2}\right].8\)
\(=8+3-1+\left[4.2\right].8\)
\(=8+3-1+8.8\)
\(=10+64=74\)
Chúc bạn học tốt!!