\(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)
=\(8\dfrac{2}{7}-3\dfrac{4}{9}-4\dfrac{2}{7}\)
=\(\left(8\dfrac{2}{7}-4\dfrac{2}{7}\right)-3\dfrac{4}{9}\)
=\(\left[\left(8-4\right)+\left(\dfrac{2}{7}-\dfrac{2}{7}\right)\right]-3\dfrac{4}{9}\)
= [4+0]-\(3\dfrac{4}{9}\)
= 4-\(3\dfrac{4}{9}\)
=\(\dfrac{5}{9}\)
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