1\(\dfrac{13}{15}.0,75-\left(\dfrac{104}{195}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)
=\(\dfrac{28}{15}.\dfrac{3}{4}-\dfrac{47}{60}.\dfrac{24}{47}-\dfrac{51}{13}.\dfrac{1}{3}\)
=\(\dfrac{7}{5}-\dfrac{2}{5}-\dfrac{17}{13}\)
=\(1-\dfrac{17}{13}\)
=\(-\dfrac{4}{13}\)