Question

Tính:

1) A= {136-32. [25:25+17. 2016⁰) :3 -3!]} : 102.52

2) B= 203-150 [(24- 9² : 3²).23 +40] : (52.22) +23.6

3)C= {(125:5²+15) - [120: (12.3²+12)]} .13-22

Answer 1

1) \(A=\left\{136-32.\left[\left(25:25+17.2016^0\right):3-3\right]\right\}:102.52\)

\(\Rightarrow A=\left\{136-32.\left[\left(1+17\right):3-3\right]\right\}:102.52\)

\(\Rightarrow A=\left[136-32.\left(18:3-3\right)\right]:102.52\)

\(\Rightarrow A=\left[136-32.\left(6-3\right)\right]:102.52\)

\(\Rightarrow A=\left(136-32.3\right):102.52\)

\(\Rightarrow A=\left(136-96\right):102.52\)

\(\Rightarrow A=40:102.52\)

\(\Rightarrow A=\dfrac{20}{51}.52\)

\(\Rightarrow A=\dfrac{1040}{51}\)