Question

tìm x,y thuộc z bít:

(x-2).(3.y+6)=0

Answer 1

(x - 2)(3y + 6) = 0

⇔ \(\left[{}\begin{matrix}x-2=0\\3y+6=0\end{matrix}\right.\)

⇔ \(\left[{}\begin{matrix}x=2\\3y=-6\end{matrix}\right.\)

⇔ \(\left[{}\begin{matrix}x=2\\y=-2\end{matrix}\right.\)

Answer 2

(x-2).(3y+6)=0

=> x-2=0

hoặc 3y+6=0

=>x=2

y= -6/3=-2