Câu hỏi của Carthrine Nguyễn

Question

Tìm x,y biết:  x + (-31/12)^2 = (49/12)^2  - x = y^2

Natsu Dragneel · Accepted Answer

Ta có :

$x+\left(\dfrac{-31}{12}\right)^2=\left(\dfrac{49}{12}\right)^2-x$

$\Rightarrow2x+\dfrac{31^2}{12^2}=\dfrac{49^2}{12^2}\Rightarrow2x=\dfrac{49^2-31^2}{12^2}=10$

$\Rightarrow x=5$

$\Rightarrow y^2=\left(\dfrac{49}{12}\right)^2-5=\dfrac{1681}{144}$

$\Rightarrow y=\dfrac{41}{12}$Câu trả lời: Ta có :

$x+\left(\dfrac{-31}{12}\right)^2=\left(\dfrac{49}{12}\right)^2-x$

$\Rightarrow2x+\dfrac{31^2}{12^2}=\dfrac{49^2}{12^2}\Rightarrow2x=\dfrac{49^2-31^2}{12^2}=10$

$\Rightarrow x=5$

$\Rightarrow y^2=\left(\dfrac{49}{12}\right)^2-5=\dfrac{1681}{144}$

$\Rightarrow y=\dfrac{41}{12}$

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