Question

Tìm x,y biết:

/x-2/=x

(x+1/2)^20+(y-1/3)^40 < 1

Answer 1

1) \(\left|x-2\right|=x\)

th1 : \(x\ge2\) thì \(\left|x-2\right|=x\Leftrightarrow x-2=x\Leftrightarrow-2=0x\)(vô lí)

th2 : \(x< 2\) thì \(\left|x-2\right|=x\Leftrightarrow2-x=x\Leftrightarrow2=2x\Leftrightarrow x=1\)(tmđk)

vậy \(x=1\)

Answer 2

b)

\(\left(x+\dfrac{1}{2}\right)^{20}\ge0\)

\(\left(x-\dfrac{1}{3}\right)^{40}\ge0\)

Mà:

\(\left(x+\dfrac{1}{2}\right)^{20}+\left(x-\dfrac{1}{3}\right)^{40}< 1\)

\(\Leftrightarrow x\in\left\{\varnothing\right\}\)