Question

tim x:(x+1)^2/8=8/x+1

Answer 1

\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\\ \Rightarrow\left(x+1\right)^2\left(x+1\right)=8\cdot8\\ \left(x+1\right)^3=64\\ \left(x+1\right)^3=4^3\\ \Rightarrow x+1=4\\ x=3\)

Answer 2

\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\)

\(\Leftrightarrow\left(x+1\right)^3=64=4^3\)

\(\Leftrightarrow x+4=1\Rightarrow x=3\)

Answer 3

\(\dfrac{\left(x+1\right)^2}{8}=\dfrac{8}{x+1}\)

=>\(\left(x+1\right)^2\left(x+1\right)=8.8\)

=>\(\left(x+1\right)^3=64\)

=>\(\left(x+1\right)^3=4^3\)

=>\(x+1=4\)

=>\(x=3\)