Giải:
Ta có: \(x.x+3x-13⋮x+3\)
\(\Rightarrow x\left(x+3\right)-13⋮x+3\)
\(\Rightarrow13⋮x+3\)
\(\Rightarrow x+3\in\left\{1;-1;13;-13\right\}\)
\(\left\{\begin{matrix}x+3=1\\x+3=-1\\x+3=13\\x+3=-13\end{matrix}\right.\Rightarrow\left\{\begin{matrix}x=-2\\x=-4\\x=10\\x=-16\end{matrix}\right.\)
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