(2x + 1)5 = (2x + 1)7
TH1:
2x + 1 = 0
2x = -1
x = -1/2
TH2:
2x + 1 = 1
2x = 1 - 1
2x = 0
x = 0
TH3:
2x + 1 = -1
2x = -1 - 1
2x = -2
x = -2 : 2
x = -1
Vậy x = -1 hoặc x = 0 hoặc x = -1/2
(2x + 1)^5 = (2x + 1)^7
TH1:
2x + 1 = 0
2x = -1
x = -1/2
TH2:
2x + 1 = 1
2x = 1 - 1
2x = 0
x = 0
TH3:
2x + 1 = -1
2x = -1 - 1
2x = -2
x = -2 : 2
x = -1
Vậy x = -1 hoặc x = 0 hoặc x = -1/2