⇔\(\sqrt{x^2-2x.3+3^2}=\sqrt{\left(\sqrt{3}\right)^2+2.\sqrt{3}.1+1}\)
⇔\(\sqrt{\left(x-3\right)^2}=\sqrt{\left(\sqrt{3}+1\right)^2}\)
⇔\(\left|x-3\right|=\left|\sqrt{3}+1\right|\)
⇔\(x-3=\sqrt{3}+1\) hoặc \(3-x=\sqrt{3}+1\)
TH1: \(x=\sqrt{3}+4\)
TH2: \(x=2-\sqrt{3}\)
Kiểm tra lại nha ^^