Question

Tìm x trong các biểu thức sau:

120+(34+3x)-(6+x)=0

\(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)

Answer 1

1)120 + ( 34 + 3x ) - ( 6 + x ) = 0

=> 120 + 34 + 3x - 6 - x = 0

=> ( 120 + 34 - 6 ) + ( 3x - x ) = 0

=> 148 + 2x = 0

=> - 2x = 148 => x = 148 : ( - 2 )

=> x = -74

Vậy x = - 74

2)\(\dfrac{-5}{6}-x=\dfrac{7}{12}+\left(\dfrac{-1}{3}\right)\)

\(=>x=\dfrac{-5}{6}-\left(\dfrac{7}{12}-\dfrac{1}{3}\right)\)

\(=>x=\dfrac{-5}{6}-\dfrac{7}{12}+\dfrac{1}{3}\)

\(=>x=\dfrac{-10}{12}-\dfrac{7}{12}+\dfrac{4}{12}\)

\(=>x=\dfrac{-10-7+4}{12}=\dfrac{-13}{12}\)

Vậy x = \(\dfrac{-13}{12}\)

tick cho mk nha