\(\sqrt{3+2\sqrt{x}}+\sqrt{x}=6\)
\(\Leftrightarrow\left(\sqrt{3+2\sqrt{x}}-3\right)+\left(\sqrt{x}-3\right)=0\)
\(\Leftrightarrow\dfrac{3+2\sqrt{x}-9}{\sqrt{3+2\sqrt{x}}+3}+\left(\sqrt{x}-3\right)=0\)
\(\Leftrightarrow\dfrac{2\left(\sqrt{x}-3\right)}{\sqrt{3+2\sqrt{x}}+3}+\left(\sqrt{x}-3\right)=0\)
\(\Leftrightarrow\left(\dfrac{2}{\sqrt{3+2\sqrt{x}}+3}+1\right)\left(\sqrt{x}-3\right)=0\)
Pt \(\dfrac{2}{\sqrt{3+2\sqrt{x}}+3}+1=0\) vô no
\(\Rightarrow\sqrt{x}-3=0\)
\(\Leftrightarrow x=9\) (nhận)
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