Question

Tìm \(x\), biết :

\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)

Answer 1

Ta có: \(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)

\(\Leftrightarrow48x^2-12x-20x+5+3x-48x^2-7+112x=81\)

\(\Leftrightarrow83x-2=81\)

\(\Leftrightarrow83x=81+2=83\)

\(\Leftrightarrow x=1\)

Answer 2

(12x – 5)(4x – 1) + (3x – 7)(1 – 16x) = 81.

48x² – 12x – 20x + 5 + 3x – 48x² – 7 + 112x = 81.

83x – 2 = 81.

83x = 83.

x = 1.

Answer 3

Ta co:(12x-5)(4x-1) +(3x-7)(1-16x)=81

⇔48x²-12x -20x +5 +3x-48x² -7 ++112x=81

⇔83x-2=81

⇔83x=81 +2=83

⇔x = 1

Chuc ban hoc tot❓❗⛇