Giải:
a) \(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)
\(\Leftrightarrow\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0\)
\(\Leftrightarrow\dfrac{11}{15}x-\dfrac{2}{5}=0\)
\(\Leftrightarrow\dfrac{11}{15}x=\dfrac{2}{5}\)
\(\Leftrightarrow x=\dfrac{6}{11}\)
Vậy ...
b) \(3\left(x-\dfrac{1}{2}\right)-5\left(x+\dfrac{3}{5}\right)=x+\dfrac{1}{5}\)
\(\Leftrightarrow3x-\dfrac{3}{2}-5x-3=x+\dfrac{1}{5}\)
\(\Leftrightarrow-2x-\dfrac{9}{2}=x+\dfrac{1}{5}\)
\(\Leftrightarrow-3x=\dfrac{47}{10}\)
\(\Leftrightarrow x=\dfrac{-47}{30}\)
Vậy ...
a, 1/3 . x + 2/5 . ( x - 1 ) = 0
1/3 . x + 2/5 . x - 2/5 = 0
x . ( 1/3 + 2/5 ) = 0 + 2/5
x . 11/15 = 2/5
x = 2/5 : 11/15
x = 6/11
b, 3 . ( x - 1/2 ) - 5 . ( x + 3/5 ) = x + 1/5
3 . x - 3 . 1/2 - 5 . x + 5. 3/5 = x + 1/5
3x - 3/2 - 5x + 3 = x + 1/5
3x - 5x + x = 1/5 + 3/2 - 3
-3x = -13/10
x = -13/10 : -1
x = -13/10
