a) \(\frac{x-2}{3}=\frac{x+1}{4}\)
=> (x - 2).4 = 3.(x + 1)
=> 4x - 8 = 3x + 3
=> 4x - 3x = 3 + 8
=> x = 11
Vậy x = 11
b) \(2.\left(x+3\right)-\frac{1}{2}=x-1\)
=> \(2x+6-\frac{1}{2}=x-1\)
=> \(2x+\frac{11}{2}=x-1\)
=> \(2x-x=-1-\frac{11}{2}\)
=> \(x=-\frac{13}{2}\)
Vậy \(x=-\frac{13}{2}\)
Bài 14 : Tìm x biết :
a) x: \(4\frac{1}{3}=-2,5\) b) x: \(\frac{-3}{5}=\frac{-10}{21}\) c) \(\frac{2}{3}x-\frac{1}{2}=\frac{1}{10}\) d) \(\frac{1}{2}x+\frac{1}{2}=\frac{5}{2}\)
Tìm x biết
a) x + \(2\frac{3}{4}=5\frac{2}{3}\)
b)X x \(3\frac{1}{2}=4\frac{3}{4}\)
c) x - \(4\frac{1}{5}=3\frac{2}{7}\)
d) x - \(\frac{3}{4}=6\text{x}\frac{3}{8}\)
e) \(\frac{7}{8}:x=3\frac{1}{2}\)
Cho p/s:
A=\(\frac{-5}{x+3}\)
a/ tìm x để A có nghĩa.
b/Tính A khi x=-2
c/ tìm x thuộc Z sao cho A thuộc Z. (Giúp tớ bài này với!!!!)
tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
Bài 14 : Tìm x biết :
e) \(\frac{-2}{3}-\frac{1}{3}\left(2x-5\right)=\frac{3}{2}\) g) \(\frac{2}{5}x+\frac{1}{2}=\frac{-3}{4}\) h) \(\frac{1}{3}x-8=\frac{1}{2}\) i) \(x-\frac{1}{4}=\frac{5}{8}.\frac{2}{3}\)
Tìm x:
a) \(\frac{x}{5}+\frac{1}{2}=\frac{x}{2}\) b) \(\frac{x}{6}=\frac{x}{2}+3\)
c) \(\frac{x-1}{4}+\frac{3}{4}=\frac{2x+1}{2}\) c) x2 -7x + 12 = 0
BT 1 TÌM X
A, \(\frac{3}{4}x+1=2\)
b, \(\frac{2}{3}+\frac{1}{3}:x=-1\)
c , |2x-1|=5
Bài 1: tìm x:
a)\(\frac{2}{3}\).x-\(\frac{3}{2}\).x=\(\frac{5}{12}\)
b) \(\frac{7}{9}\):(2+\(\frac{3}{4}\).x)+\(\frac{5}{9}\)=\(\frac{23}{27}\)
c)\(\frac{2}{5}\)+\(\frac{3}{5}\).(3x-3,7)= -\(\frac{53}{10}\)
tìm số x , biết :
a) \(\frac{2}{3}x-\frac{3}{2}x=\frac{5}{12}\)
b) \(\frac{2}{5}+\frac{3}{5}.\left(3x-3,7\right)=\frac{-53}{10}\)
c) \(\frac{7}{9}:\left(2+\frac{3}{4}x\right)+\frac{5}{9}=\frac{23}{27}\)
d) \(\frac{-2}{3}.x+\frac{1}{5}=\frac{3}{10}\)
e) \(\left|x\right|-\frac{3}{4}=\frac{5}{3}\)
f) \(\left|2x-\frac{1}{3}\right|+\frac{5}{6}=1\)
