a. \(\dfrac{3}{4}\) : x - \(\dfrac{17}{5}\) = \(\dfrac{7}{10}\)
\(\dfrac{3}{4}\) : x = \(\dfrac{7}{10}\) + \(\dfrac{17}{5}\)
\(\dfrac{3}{4}\) : x = \(\dfrac{41}{10}\)
x = \(\dfrac{3}{4}\) : \(\dfrac{41}{10}\)
x = \(\dfrac{3}{4}\) . \(\dfrac{10}{41}\)
x = \(\dfrac{15}{82}\)
Vậy x = \(\dfrac{15}{82}\)
a, \(\dfrac{3}{4}:x-\dfrac{17}{5}=\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{4}:x=\dfrac{7}{10}+\dfrac{17}{5}\)
\(\Rightarrow\dfrac{3}{4}:x=\dfrac{41}{10}\)
\(\Rightarrow x=\dfrac{3}{4}:\dfrac{41}{10}\)
\(\Rightarrow x=\dfrac{15}{82}\)
b, \(\dfrac{2}{7}+\dfrac{5}{7}x=\dfrac{8}{21}\)
\(\Rightarrow\dfrac{5}{7}x=\dfrac{8}{21}-\dfrac{2}{7}\)
\(\Rightarrow\dfrac{5}{7}x=\dfrac{2}{21}\)
\(\Rightarrow x=\dfrac{2}{21}:\dfrac{5}{7}\)
\(\Rightarrow x=\dfrac{2}{15}\)
c, \(\dfrac{11}{5}-\dfrac{6}{5}:x=\dfrac{4}{7}\)
\(\Rightarrow\dfrac{6}{5}:x=\dfrac{11}{5}-\dfrac{4}{7}\)
\(\Rightarrow\dfrac{6}{5}:x=\dfrac{57}{35}\)
\(\Rightarrow x=\dfrac{6}{5}:\dfrac{57}{35}\)
\(\Rightarrow x=\dfrac{14}{19}\)
d, \(\dfrac{-3}{4}x+\dfrac{3}{4}=\dfrac{11}{12}\)
\(\Rightarrow\dfrac{-3}{4}x=\dfrac{11}{12}-\dfrac{3}{4}\)
\(\Rightarrow\dfrac{-3}{4}x=\dfrac{1}{6}\)
\(\Rightarrow x=\dfrac{1}{6}:\dfrac{-3}{4}\)
\(\Rightarrow x=\dfrac{-2}{9}\)