b, \(\left|2x+3\right|=5\)
\(\Rightarrow\left[\begin{matrix}2x+3=5\\2x+3=-5\end{matrix}\right.\Rightarrow\left[\begin{matrix}2x=2\\2x=-8\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=1\\x=-4\end{matrix}\right.\)
Vậy, x = 1 hoặc x = -4.
c, \(2-x=17-\left(-5\right)\)
\(\Rightarrow2-x=17+5\)
\(\Rightarrow2-x=22\)
\(\Rightarrow x=2-22\)
\(\Rightarrow x=-20\)
https://hoc24.vn/hoi-dap/question/181523.html
a, \(3\left|x-2\right|=3\)
\(\Rightarrow\left|x-2\right|=1\)
\(\Rightarrow\left|x\right|=3\)
\(\Rightarrow\left[\begin{matrix}x=3\\x=-3\end{matrix}\right.\)
Vậy, x = 3 hoặc x = -3.
a. 3.|x-2|=3
|x-2|=1
=> x-2 = 1 hay x-2 = -1
=> x=3 hay x=1
Vậy x=3;x=1
b. |2x+3|=5
=> 2x+3=5 hay 2x+3=-5
=> 2x = 2 hay 2x = -8
=> x=1 hay x=-4
Vậy x=1;x=-4
c. 2-x=17-(-5)
2-x = 22
x= -20
Vậy x=-20
d. 8-|x+3|=16:23
8-|x+3|=2
|x+3|=4
=> x+3=4 hay x+3=-4
=> x = 1 hay x = -7
Vậy x=1;x=-7
d, \(8-\left|x+3\right|=\frac{16}{2^3}\)
\(\Rightarrow8-\left|x+3\right|=\frac{2^4}{2^3}\)
\(\Rightarrow8-\left|x+3\right|=2\)
\(\Rightarrow\left|x+3\right|=6\)
\(\Rightarrow\left[\begin{matrix}x+3=6\\x+3=-6\end{matrix}\right.\Rightarrow\left[\begin{matrix}x=3\\x=-9\end{matrix}\right.\)
Vậy, x = 3 hoặc x = -9.
a) 3.|x-2|=3
=> |x-2|=3:3
=> |x-2|= 1
=> |x|=1+2
=> |x|=3
=> x =3
b) |2x+3|=5
TH1:|2x+3|=5
=> |2x|=5-3
=> |2x|= 2
=> |x|=2:2
=> |x|=1
=> x=1
TH2: |2x+3|=-5
=> |2x| =(-5)-3
=> |2x| =-8
=> |x| =(-8):2
=> |x|= -4
=> x=-4
c) 2-x=17-(-5)
=> 2-x=22
=> x= 2-22
=> x=-20