a) \(\frac{2}{3}x=\frac{5}{6}\)
\(x=\frac{5}{6}:\frac{2}{3}\)
\(x=\frac{5}{4}\)
Vậy \(x=\frac{5}{4}\)
b) \(2x+\frac{2}{3}=\frac{5}{6}\)
\(2x=\frac{5}{6}-\frac{2}{3}\)
\(2x=\frac{1}{6}\)
\(x=\frac{1}{6}:2\)
\(x=\frac{1}{12}\)
Vậy \(x=\frac{1}{12}\)
a) \(\dfrac{2}{3} \)x=\(\dfrac{5}{6}\)
x= \(\dfrac{5}{6} : \dfrac{2}{3}\)
x=\(\dfrac{5}{6}\)x\(\dfrac{3}{2}\)
x=\(\dfrac{5}{4} \)
Vậy x= \(\dfrac{5}{4}\)
b) 2x + \(\dfrac{2}{3} \) =\(\dfrac{5}{6}\)
2x =\(\dfrac{5}{6}\)- \(\dfrac{2}{3} \)
2x =\(\dfrac{5}{6}\)-\(\dfrac{4}{6}\)
2x =\(\dfrac{1}{6}\)
x = \(\dfrac {1}{6} :2\)
x= \(\dfrac{1}{12}\)
Vậy x= \(\dfrac{1}{12}\)
\(\dfrac{1}{12}\)\(\dfrac{1}{12}\)\(\dfrac{1}{12}\)\(\dfrac{1}{6}\)