Ta có: \(18x+3⋮7\)
\(\Leftrightarrow18x+3-21⋮7\)
\(\Leftrightarrow18x-18⋮7\)
\(\Leftrightarrow18\left(x-1\right)⋮7\)
Vì \(18⋮̸7\)
nên \(x-1⋮7\)
\(\Leftrightarrow x-1\in B\left(7\right)\)
\(\Leftrightarrow x-1\in7k\left(k\in N\right)\)
\(\Leftrightarrow x=7k+1\left(k\in N\right)\)
Vậy: x=7k+1(k∈N)