Ta có:
\(\dfrac{3}{7}\)=\(\dfrac{15}{35}\);\(\dfrac{5}{8}\)=\(\dfrac{15}{24}\)
Lại có:\(\dfrac{15}{35}\)<x<\(\dfrac{15}{24}\)
Vậy x={\(\dfrac{15}{34}\);\(\dfrac{15}{33}\).....;\(\dfrac{15}{25}\)}
gọi p/s cần tìm là a
ta có :
\(\dfrac{3}{7}\)< a <\(\dfrac{5}{8}\)
=> \(\dfrac{15}{35}\)<a<\(\dfrac{15}{24}\)
=> a \(\in\)\(\left\{\dfrac{15}{34};\dfrac{15}{33};...;\dfrac{15}{25}\right\}\)
gọi phân số cần tìm là a
\(\dfrac{3}{7}\)< a <\(\dfrac{5}{8}\)
\(\dfrac{5}{8}\)= \(\dfrac{15}{24}\)
\(\dfrac{3}{7}\)= \(\dfrac{15}{21}\)
=> \(\dfrac{15}{21}\)<a<\(\dfrac{15}{24}\)
=> a\(\in\) \(\left\{\dfrac{15}{22};\dfrac{15}{23}\right\}\)
x \(\in\) \(\left\{\dfrac{15}{34};\dfrac{15}{33};\dfrac{15}{32};...;\dfrac{15}{25}\right\}\)
nhá like cho mk đó