Vì : \(x+12⋮x+3;x+3⋮x+3\)
\(\Rightarrow\left(x+12\right)-\left(x+3\right)⋮x+3\Rightarrow9⋮x+3\)
Mà : \(x+3\ge3\Rightarrow x+3\in\left\{3;9\right\}\Rightarrow x\in\left\{0;6\right\}\)
x + 12 \(⋮\)x + 3
=> x + 3 + 9 \(⋮\)x + 3
vì x + 3 \(⋮\)x + 3
=> 9 \(⋮\)x + 3
=> x + 3 \(\in\) Ư (9) = {1; 3; 9}
=> x \(\in\) {0; 6}
Vậy x \(\in\) {0; 6}
Chúc bạn học tốt!