\(\left(2n+1\right)^3=27\)
\(\Rightarrow\left(2n+1\right)^3=3^3\)
\(\Rightarrow2n+1=3\)
\(\Rightarrow2n=3-1=2\)
\(\Rightarrow n=2:2=1\)
Vậy n =1
\(\left(2n+1\right)^3=27\)
\(\Rightarrow2n+1=3\)
\(\Rightarrow2n=2\Rightarrow n=1\)
(2n + 1)3 = 27
(2n + 1)3 = 33
\(\Rightarrow\) 2n + 1 = 3
2n = 3 - 1
2n = 2
n = 2 : 2
n = 1.