a) \(x+\left(-35\right)=18\)
\(x=18-(-35)\)
\(x=18+35\)
\(x=53\)
Vậy x = 53
b) \(-2x-\left(-17\right)=15\)
\(-2x+17=15\)
\(-2x=-2\)
\(x=-2:(-2)\)
\(x=1\)
Vậy \(x=1\)
a) x+(-35)=18
=>x = 18+35
=>x = 53
b) -2x-(-17) = 15
=> -2x = 17-15
=> -2x = 2
=> x = -1