Theo đề, ta có:
a : b = \(\dfrac{3}{2}\)
a = \(\dfrac{3}{2}\)b (1)
a - b = 8 (2)
Thế (1) vào (2)
\(\dfrac{3}{2}\)b - b = 8
\(\dfrac{1}{2}\)b = 8
b = 8 :\(\dfrac{1}{2}\)
b = 16
a = 24
Theo đề bài ta có:
a : b =\(\dfrac{3}{2}\) và a - b = 8
=> a= \(\dfrac{3}{2}\) .b
Vs a = \(\dfrac{3}{2}\).b
=> \(\dfrac{3}{2}\) .b - b.1 = 8
=> b.(\(\dfrac{3}{2}\) - 1) =8
=> b. \(\dfrac{1}{2}\) = 8
=> b = 8 : \(\dfrac{1}{2}\)
=> b = 8 . \(\dfrac{2}{1}\)
=> b = 16
Vs b =16
=> a = \(\dfrac{3}{2}\). 16
=> a = \(\dfrac{3.16}{2}\)
=> a = 24
Vậy a = 24
b = 16