Question

thực hiện phép tính :

\(|x+\dfrac{1}{2}|-\dfrac{2}{3}=\sqrt{\dfrac{16}{9}}\)

Answer 1

\(\Leftrightarrow\left|x+\dfrac{1}{2}\right|=\dfrac{4}{3}+\dfrac{2}{3}\Leftrightarrow\left|x+\dfrac{1}{2}\right|=2\)

TH1:Với \(x\ge0:\) \(x+\dfrac{1}{2}=2\Leftrightarrow x=2-\dfrac{1}{2}\Leftrightarrow x=\dfrac{3}{2}\)(TMĐK)

TH2: Với \(x< 0:\) \(\dfrac{-1}{2}-x=2\Leftrightarrow-x=2+\dfrac{1}{2}\Leftrightarrow-x=\dfrac{5}{2}\Leftrightarrow x=\dfrac{-5}{2}\)(TMĐK)

Vậy \(x=\dfrac{3}{2};x=\dfrac{-5}{2}\)