a: \(=\dfrac{2}{3}-\dfrac{2}{5}=\dfrac{10-6}{15}=\dfrac{4}{15}\)
b: \(=\dfrac{9}{12}-\dfrac{10}{12}+\dfrac{11}{12}=\dfrac{10}{12}=\dfrac{5}{6}\)
c: \(=\dfrac{1}{4}-\dfrac{3}{2}+\dfrac{1}{2}\cdot\dfrac{12}{5}+\dfrac{1}{20}=\dfrac{-5}{4}+\dfrac{6}{5}+\dfrac{1}{20}=0\)
d: \(=\dfrac{1}{25}\cdot\dfrac{20}{15}+\left(\dfrac{1}{4}-\dfrac{5}{6}\right):\dfrac{14}{3}=-\dfrac{43}{600}\)