\(\dfrac{22}{7}\cdot\dfrac{-2}{11}+\dfrac{3}{2}\cdot\dfrac{4}{9}:\left(-4\right)^2\\ =\dfrac{22}{7}\cdot\dfrac{-2}{11}+\dfrac{3}{2}\cdot\dfrac{4}{9}:16\\ =\dfrac{22}{7}\cdot\dfrac{-2}{11}+\dfrac{3}{2}\cdot\dfrac{4}{9}\cdot\dfrac{1}{16}\\ =\dfrac{-4}{7}+\dfrac{2}{3}\cdot\dfrac{1}{16}\\ =\dfrac{-4}{7}+\dfrac{1}{24}\\ =\dfrac{-96}{168}+\dfrac{7}{168}\\ =\dfrac{91}{168}\)
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Bạn làm sai rồi.
\(\dfrac{22}{7}.\dfrac{-2}{11}=\dfrac{-4}{7}\) chứ ko phải bằng \(\dfrac{4}{7}\) .
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