Question

\(\sqrt{2-\sqrt{3}}\left(\sqrt{5}+\sqrt{2}\right)\)

Answer 1

Sửa đề: \(\sqrt{2-\sqrt3}\left(\sqrt6+\sqrt2\right)\)

Ta có: \(\sqrt{2-\sqrt3}\left(\sqrt6+\sqrt2\right)\)

\(=\sqrt{4-2\sqrt3}\left(\sqrt3+1\right)\)

\(=\sqrt{\left(\sqrt3-1\right)^2}\cdot\left(\sqrt3+1\right)=\left(\sqrt3-1\right)\left(\sqrt3+1\right)\)

=3-1

=2