Ta có \(\sqrt{5a^2-4a\sqrt{5}+4}\) (1)
= \(\sqrt{\left(a\sqrt{5}-2\right)^2}\)
=\(|a\sqrt{5}-2|\)
Mà a= \(\sqrt{5}+\dfrac{1}{\sqrt{5}}\) > 0
nên (1) = \(a\sqrt{5}-2\)
suy ra ( \(\sqrt{5}+\dfrac{1}{\sqrt{5}}\))\(\sqrt{5}\) - 2
=5 + 1- 2
=4
vậy ...