Giải:
Ta có: \(R_3//R_6\)
Nên: \(R_{36}=\dfrac{R_3.R_6}{R_3+R_6}=\dfrac{3.6}{3+6}=2\left(\Omega\right)\)
Mà: \(R_2ntR_{36}\)
Nên: \(R_{236}=R_2+R_{36}=2+2=4\left(\Omega\right)\)
\(R_5//R_{236}\) nên: \(R_{5236}=\dfrac{R_5.R_{236}}{R_5+R_{236}}=\dfrac{5.4}{5+4}=\dfrac{20}{9}\left(\Omega\right)\)
Mà: \(R_1ntR_{5236}\) nên: \(R_{15236}=R_1+R_{5236}=1+\dfrac{20}{9}=\dfrac{29}{9}\left(\Omega\right)\)
Mặt khác: \(R_4//R_{15236}\)
Nên: \(R_{td}=R_{415236}=\dfrac{R_4.R_{15236}}{R_4+R_{15236}}=\dfrac{116}{65}\left(\Omega\right)\)
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