a: \(=\dfrac{15}{40}-\dfrac{8}{40}+\dfrac{3}{40}=\dfrac{10}{40}=\dfrac{1}{4}\)
b: \(=\dfrac{68}{72}-\dfrac{132}{72}+\dfrac{16}{72}=\dfrac{-48}{72}=\dfrac{-2}{3}\)
c: \(=\dfrac{48}{90}-\dfrac{35}{90}-\dfrac{13}{90}=0\)
e: \(=\dfrac{3}{4}-\dfrac{17}{60}+\dfrac{3}{5}=\dfrac{45-17+36}{60}=\dfrac{64}{60}=\dfrac{16}{15}\)