Nhận thấy \(cos4x=0\) ko phải nghiệm, chia 2 vế cho \(cos^24x\)
\(3+5tan^24x=2\left(1+tan^24x\right)-2\sqrt{3}tan4x\)
\(\Leftrightarrow3tan^24x+2\sqrt{3}tan4x+1=0\)
\(\Rightarrow tan4x=-\frac{\sqrt{3}}{3}=tan\left(-\frac{\pi}{6}\right)\)
\(\Rightarrow4x=-\frac{\pi}{6}+k\pi\Rightarrow x=-\frac{\pi}{24}+\frac{k\pi}{4}\)