Gọi \(\left\{{}\begin{matrix}n_{SO2}:a\left(mol\right)\\n_{O2}:b\left(mol\right)\\n_X=0,5\left(mol\right)\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a+b=0,5\\\frac{64a+32b}{0,5}=22,4.2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}a=0,2\\b=0,3\end{matrix}\right.\)
\(PTHH:2SO_2+O_2⇌2SO_3\)
Phứng :__x_____0,5x_____x
=> Dư \(\left\{{}\begin{matrix}0,2-x\left(mol\right)SO_2\\0,3-0,5x\left(mol\right)O_2\end{matrix}\right.\)
Tạo x mol SO3
\(Ba\left(OH\right)_2+SO_2\rightarrow BaSO_3+H_2O\)
__________0,2-x_______0,2-x___________
\(Ba\left(OH\right)_2+SO_3\rightarrow BaSO_4+H_2O\)
___________x______x_____________
\(\Rightarrow217.\left(0,2-x\right)+233x=44,2\)
\(\Leftrightarrow x=0,05\)
\(\Rightarrow H=\frac{0,05.100}{0,2}=25\%\)
