\(m_C=\dfrac{46\cdot52,17}{100}=24\left(g\right);m_O=\dfrac{46\cdot34,78}{100}=16;m_H=\dfrac{46\cdot13,05}{100}=6\left(g\right)\)
\(=>n_C=\dfrac{24}{12}=2\left(mol\right);n_H=\dfrac{6}{1}=6\left(mol\right);n_O=\dfrac{16}{16}=1\left(mol\right)\)
\(=>CTHH:C_2H_6O\)